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标题: GSON详细解析 [打印本页]

作者: admin 时间: 2016-3-7 10:18
标题: GSON详细解析
GSON项目源代码地址
https://github.com/google/gson

最新的jar下载地址（去下面网址搜索gson）
http://mvnrepository.com/

下载下来的目录结构
CHANGELOG.md
examples
gson
lib
metrics
proto
ReleaseProcess.md
codegen
extras
GsonDesignDocument.md
LICENSE
pom.xml
README.md
UserGuide.md

#需求
gson是常用的框架

#分析
1.如何解析数组
```
[
  {
"id": "1",
"tag": "tag1",
"tobe": "tobe1"
  },
  {
"id": "2",
"tag": "tag2",
"tobe": "tobe2"
  }
]
```
```
Gson gson = new Gson();
Course[] courses = gson.fromJson(sg.toString(), Course[].class);
```
2.带数据头的数组数据
```
{
  "code":"1",
  "msg":"success",
  "data":[
{ "id": "1",
   "info": "1连",
   "parent_id":"0",
   "tobe": "tobe1"
},
{ "id": "2",
   "info": "2连",
   "parent_id":"1",
   "tobe": "tobe1"
},
{ "id": "3",
   "info": "3连",
   "parent_id":"2",
   "tobe": "tobe1"
}
  ]
}

public class DataHead<T> {

public int code;

public String msg;

@SerializedName(value = "datas",alternate = {"data","dataa"})
public T[] datas;
}

Gson gson = new Gson();
Type unitType = new TypeToken<DataHead<Unit>>(){}.getType();
DataHead<Unit> head = gson.fromJson(str,unitType);
return head.datas;

```

3.jsonReader使用

4.遇到空字符串时如果转换类型会报错的

#过程

1

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